Here comes a grand number: N = 1^{1986} + 2^{1986 }+ 3^{1986} + 4^{1986}.

Can you find its last digit?

**Hint**
Let’s start with 2^{1986}. Can we write it as product
of factors whose last digits are easy to
determine?
What number, power of 2, yields the same last
digit when raised to any power?
It’s 16 = 2^{4}.
16 raised to any power will give a number that
ends in 6 (because 6 raised to any power gives a
number that ends is 6. Always.)

Check your answer

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